Posted: Tue Jan 20, 2009 5:47 am
i break big pieces of metal with a fall factor of 2.
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It's my fault you got confused, my diagram in the first two doesn't actually show where the person fell from, but I thought that was obvious.caribe wrote:Redpoint: In your first depiction it is fall factor 1/3 at most and this is fairly normal.
(Fall factor) = (length of fall)/ (length of rope paid out)
Likewise the second picture from the left is fall factor = 1/2 at most (if there is no more movement in the system after all the action has occurred, the fall factor is less than 1/2).
The third picture from the left is labeled correctly. fall factor = 2 <minus the amount of static elongation in the line due to the climber's weight>
The fourth picture is labeled correctly also. Since the rope did not experience the fall, the fall factor must be 0.
Some balls are held for charity and some for fancy dress-Redpoint wrote: I am sure that it takes bigger balls to climb trad than it does sport
___ I was wrong. Your first depiction was ff<2/3 if I give you the benefit of the doubt on those distances.Redpoint wrote:It's my fault you got confused, my diagram in the first two doesn't actually show where the person fell from, but I thought that was obvious.caribe wrote:Redpoint: In your first depiction it is fall factor 1/3 at most and this is fairly normal.
(Fall factor) = (length of fall)/ (length of rope paid out).
___ http://tinyurl.com/aje8y4 <Craig Luebben, Mechanical Engineer, inventor of Big Bros.Redpoint wrote: From what I remember reading, static elongation is already in the formula, because it is how far the climber has fallen(which includes the static elongation), divided by how much rope is paid out.
caribe wrote:Redpoint wrote:caribe wrote: ___ I don't think that the Fall factor accounts for stretch in rope. The rope stretch is not as aspect of the fall factor per se. For example a factor 1 fall on a dynamic rope (6% static elongation) is going to have a much lower maximum impact force than a factor 1 fall on a static rope (2% static elongation); even though, these fall factors will be pretty equal. This is the reason we use dynamic ropes.
You gave me an epiphany: if every book and pamphlet I ever read concerning fall factors say that 2 is the greatest fall factor, than that must mean the fall factor is factored before the rope stretches. Either that or you are right and there is no such thing as a fall factor of 2 when rock climbing.ynp1 wrote:
oh yeah and you cannot factor 2 on a dynamic rope (or a static rope for that matter, it still stretches 2%). so if you take a fall 100 feet off the belay with no pro to stop the fall you will fall the 215 feet (the extra 15 feet is from rope stretch, which i think is around 15% or maybe more with dynamic ropes) to find the fall factor you take the distance of the fall (215ft.) devided by the length of the rope (115ft). the fall factor is 1.87. you can get really close to a factor 2, but i dont think you cant factor 2 with any climbing gear. daisy falls can be very close, but daisies stretch a little. maybe if you used a steel cable instead of a rope... also the more slack your belayer gives you the lower the factor is of the fall, because you have more rope out. so if you so if you are 100 feet off the belay and your belayer has 15 of slack out your fall will be 232.25 feet (with stretch). the amount of rope with the stretch is 132.25 feet, fall factor of 1.78. that is why we all like soft catches.
its not like it really matters. climbing is safe.